Hi, I'm not sure about this. I think the above if for one person selecting the same number three times. My calculations would be: The chance of taking any one of the same number the first time would be 8/106 x 7/105 (ok, I'm allowing for the lower pool) This can happen 13 different ways so the chance for the first draw is (8/106 x 7/105) x 13 For three times in a row this number is cubed, so the chance would be ((8/106 x 7/105) x 13)^3 = 0.027% Rummikub is great